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WAEC 2020/2021 Physics Obj and Theory Questions And Answers
PHYSICS OBJ:
1-10: CBBBCACBCB
11-20: CCCABB
21-30: C-DADCD-DA
31-40: BDDBBCAABC
41-50: ABDABDBCBA
Questions No: (1)
Mass = 20g = (20/)100kg = 0.02kg
Extension = 5cm = (5/100)m = 0.05m
K = 200N/
V = ?
1/2mv² = 1/2ke²
V = √ke²/m = √200×0.05×0.05/0.02
V = √25
V = 5m/s
Questions No: (2a)
P - Initial velocity of the projectile
B - Angle of projection
H - Maximum height reached by the projectile
R - Range or the total horizontal distance covered
by the
projectile
Questions No(2b):
R=P^2 sin 2β/g
at maximum range sin2β=1
Rmax=P^2/g
This happens at β = 45degree
Questions No(3):
(i)reflection
(ii)refraction
(iii)diffraction
Questions (4):
(i)Magnetic Declination
(ii)Horizontal Component of Earth’s Magnetic Field
(iii)The angle of Dip or Magnetic Inclination
Questions No (5a):
Free electrons are electrons in a material which can
contribute to electric current.
Questions No (5b):
hole is the absence of an electron in a particular
place in
an atom
Questions No(6a):
Principle of operation of fiber optics state that the
density
of transparent glass and the refractive index is
greater than
the density of the two mirrors
Questions No (6b):
(i)it is used to view deep down the throat of a
patient
(ii)it is used to conveying information
Questions No(9a):
Latent heat is energy released or absorbed, by a
body or a
thermodynamic system, during a constant-temper
ature
process.
Questions No (9aii):
(i)surface area in contact with atmosphere
(ii)nature of the liquid
Questions No(9bi):
Clay is poorer conductor of heat than plastic
Questions No (9bii):
An increase in pressure in the cooker increase the
ambient
temperature in the cooker hence the food cooks
faster
Questions No (9c):
(i)Change in the state of a substance
(ii)Increase in temperature
Questions No (9di):
Heat supplied = m1
lvt = m1
12*40*1400=1.5*1
L=12*40*1400/1.5
L=672000/1.5= 448,000J/kg
Laten heat of fusion of the body = 4.48*10^5J/Kg
Questions No (9dii):
lvt=mc D tita
12*40*72=1.5*c*60
C=12*40*72/1.5*60
C=384J/Kg/K
Specific heat capacity of the body =384J/Kg/K
+++++++++++++++++++++++
Solving...
Typing...
Questions No (8ai):
It state that every particles in the universe attract every other particle with a force that is proportional to the product of their masses and inversely proportional to the square of the distance between them
Questions No(8aii):
Gravitational field is a region of space around a mass on which the gravitational force of the mass can be felt
Questions No (8bi):
F=GMeM/re² ------from newton's law
Where Me is mass of earth
re is the distance of mass from earth
G is a constant of gravitation
But F=GMeM/re² =mg
Me=GMe/re²=g
g=GMe/re²
Questions No (8bii):
(i)That The earth is a sphere
(ii)That g depends on mass of earth alone
Questions No (8c):
Using F = GMeM/r²
F=6.67*10^-11*5.98*10²4*2.00*10³degree/(1.50*10^8*10³)²
F= 79.7732*10^43/2.25*10²²
F=35.455*10²1
=3.5455*10²2N
Questions No (8di):
Escape velocity (Ve) is the minimum velocity required for an object (egg statelite) to just escape or leave the gravitational influence or field of an astronomical body (eg earth) permanently
(8dii)
(i)g varies across the earth but G is constant
(ii)the unit of g is m/s² while that of G is NM²/Kg²
Questions No (1)
Mass = 20g = (20/100)kg = 0.02kg
Extension = 5cm = (5/100)m = 0.05m
K = 200N/
V = ?
1/2mv² = 1/2ke²
V = √ke²/m = √200×0.05×0.05/0.02
V = √25
V = 5m/s
Questions No (9ai):
Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process.
Questions No (9aii):
(i)surface area in contact with atmosphere
(ii)nature of the liquid
Questions No (9bi):
The rate of absorption of heat by clay pot is less than the rate of absorption of heat by plastics. Also, water gets evaporated in a clay pot which the evaporation causes cooling; so water in a clay pot remains cool
Questions No (9bii):
An increase in pressure in the cooker increase the ambient temperature in the cooker hence the food cooks faster
Questions No (9c):
(i) Change in the state of a substance
(ii) Increase in temperature
Questions No (9di):
Heat supplied = m1
lvt = m1
12*40*1400=1.5*1
L=12*40*1400/1.5
L=672000/1.5= 448,000J/kg
Laten heat of fusion of the body = 4.48*10^5J/Kg
Questions No (9dii):
lvt=mc D tita
12*40*72=1.5*c*60
C=12*40*72/1.5*60
C=384J/Kg/K
Specific heat capacity of the body =384J/Kg/K
==========================
11) u= 5ms-1 u= 6ms-1
A= 1ms-2 a= 3ms-2
p→ ←a
M—————————————N
51m
Questions (11a):
t when particles are 30 meters apart
S= ut + ½ at2
Sp= st + ½ t2
Sa = 6t + 1/2 (3)t2
Where sp and sa are distances covered by particles respectively at any time t
At time, t= 1.5s
Sp = 5(1.5) + ½(1.5)2 =8.625m
sa = 6(1.5) + ½ (3)(1.5)2 = 12.375m
sp + sa = 8.625 + 12.375
= 21m
Distance between particles = 51 – 21 = 30m
At time t = 1.5s, the particles will be 30 meters apart.